RC and RL Exponential Responses: Difference between revisions

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==Summary of Equations==
{| border="1" cellspacing="0" cellpadding="5" align="center"
|+Exponential responses of C and L
|-
! !!Discharging !! Charging !! Time Constant
|-
|Capacitor || <math>v_C(t)=V_0e^{-\frac{t}{RC}}</math> || <math>v_C(t)=V_s(1-e^{-\frac{t}{RC}})</math> ||<math>RC\,</math>
|-
|Inductor || <math>i_L(t)=I_0e^{-\frac{R}{L}t}</math> || <math>i_L(t)=I_0(1-e^{-\frac{R}{L}t})</math> || <math>\frac{L}{R}</math>
|-
|}

==RC Circuits==
==RC Circuits==
===Discharging===
===Discharging===

Revision as of 20:02, 15 June 2006

Summary of Equations

Exponential responses of C and L
Discharging Charging Time Constant
Capacitor vC(t)=V0etRC vC(t)=Vs(1etRC) RC
Inductor iL(t)=I0eRLt iL(t)=I0(1eRLt) LR

RC Circuits

Discharging

Consider the following circuit:

File:RC discharge schematic.jpg

In the circuit, the capacitor is initally charged and has voltage V0 aross it, and the switch is initially open. At time t=0, we close the circuit and the capacitor will discharage through the resistor. The voltage across a capacitor discharging through a resistor as a function of time is given as:

vC(t)=V0etRC

Charging

If the capacitor is initially uncharged and we want to charge it by inserting a voltage source Vs in the RC cicuit:

File:RC charge schematic.jpg

The voltage across the capacitor is given by:

vC(t)=Vs(1etRC)

The term RC is the resistance of the resistor multiplied by the capacitance of the capacitor, and known as the time constant, which is a unit of time. The value of the function will be 63% of the final value at t=1RC, and over 99.99% of the final value at t=5RC.

The magnitudes of the voltage and current of the capacitor in the circuit above are shown in the graphs below:

Capacitor
Voltage Current
Charge File:RC charge voltage.jpg File:RC charge current.jpg
Discharge File:RC discharge voltage.jpg File:RC discharge current.jpg

RL Circuits

Discharging

In the following circuit, the inductor initally has current I0=V0/R flowing through it; we replace the voltage source with a short circuit at t=0.

File:RL discharge schematic.jpg

The current flowing through the inductor at time t is given by:

iL(t)=I0eRLt

Charging

If the inductor is initially uncharged and we want to charge it by inserting a voltage source Vs in the RL cicuit:

File:RL charge schematic.jpg

The current through the inductor is given by:

iL(t)=I0(1eRLt)

The time constant for the RL circuit is equal to L/R.

The magnitudes of the voltage and current of the inductor for the circuits above are given by the graphs below:

Inductor
Voltage Current
Charge File:RL charge voltage.jpg File:RL charge current.jpg
Discharge File:RL discharge voltage.jpg File:RL discharge current.jpg