Kirchhoff problem 2 solution

At t=0, the capacitor acts like a short circuit and the inductor acts like an open circuit, and we can simply the cicuit into:

$V_{R1}=6.818V$

$V_{R2}=0V$

$V_{R3}=V_{R4}=8.182V$

$I_{R1}=13.64mA$

$I_{R2}=0A$

$I_{R3}=5.455mA$

$I_{R4}=8.182mA$

At $t=\infty$, the capacitor acts like an open circuit and the inductor acts like a short circuit. We can then simplify the circuit:

$V_{R1}=9V$

$V_{R2}=36V$

$V_{R3}=0V$

$V_{R4}=6V$

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle I_{R1}=18mA}

$I_{R2}=12mA$

$I_{R3}=0A$

$I_{R4}=6mA$