# Kirchhoff problem 2 solution

From Mech

At t=0, the capacitor acts like a short circuit and the inductor acts like an open circuit, and we can simply the cicuit into:

*V*_{R1} = 6.818*V*

*V*_{R2} = 0*V*

*V*_{R3} = *V*_{R4} = 8.182*V*

*I*_{R1} = 13.64*m**A*

*I*_{R2} = 0*A*

*I*_{R3} = 5.455*m**A*

*I*_{R4} = 8.182*m**A*

At , the capacitor acts like an open circuit and the inductor acts like a short circuit. We can then simplify the circuit:

*V*_{R1} = 9*V*

*V*_{R2} = 36*V*

*V*_{R3} = 0*V*

*V*_{R4} = 6*V*

*I*_{R1} = 18*m**A*

*I*_{R2} = 12*m**A*

*I*_{R3} = 0*A*

*I*_{R4} = 6*m**A*