Kirchhoff problem 2 solution
From Mech
At t=0, the capacitor acts like a short circuit and the inductor acts like an open circuit, and we can simply the cicuit into:
VR1 = 6.818V
VR2 = 0V
VR3 = VR4 = 8.182V
IR1 = 13.64mA
IR2 = 0A
IR3 = 5.455mA
IR4 = 8.182mA
At , the capacitor acts like an open circuit and the inductor acts like a short circuit. We can then simplify the circuit:
VR1 = 9V
VR2 = 36V
VR3 = 0V
VR4 = 6V
IR1 = 18mA
IR2 = 12mA
IR3 = 0A
IR4 = 6mA