Kirchhoff problem 2 solution: Difference between revisions

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At t=0, the capacitor acts like a short circuit and the inductor acts like an open circuit, and we can simply the cicuit into:

$V_{R 1} = 6.818 V$

$V_{R 2} = 0 V$

$V_{R 3} = V_{R 4} = 8.182 V$

$I_{R 1} = 13.64 m A$

$I_{R 2} = 0 A$

$I_{R 3} = 5.455 m A$

$I_{R 4} = 8.182 m A$

At $t = \infty$ , the capacitor acts like an open circuit and the inductor acts like a short circuit. We can then simplify the circuit:

$V_{R 1} = 9 V$

$V_{R 2} = 36 V$

$V_{R 3} = 0 V$

$V_{R 4} = 6 V$

$I_{R 1} = 18 m A$

$I_{R 2} = 12 m A$

$I_{R 3} = 0 A$

$I_{R 4} = 6 m A$

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	At t=0, the ~~cap[[Image:acitor~~ acts like a short circuit and the inductor acts like an open circuit, and we can simply the cicuit into:		At t=0, the capacitor acts like a short circuit and the inductor acts like an open circuit, and we can simply the cicuit into:

	[[Image:kirchhoff_problem2_solution_1.jpg]]		[[Image:kirchhoff_problem2_solution_1.jpg]]